[jrubenol]

Hi All -

My wife is complaining that it's too hard to navigate through all of our media for her to find new shows that she might want to watch. She asked if there's a way for me to somehow highlight the popular shows that we have (for example, how Netflix identifies the top 10 every week on its platform). Is there any functional way to do this other than for me to create a tag an manually add shows?

Thanks in advance.

[izprtxqkft]

Hi All -

My wife is complaining that it's too hard to navigate through all of our media for her to find new shows that she might want to watch. She asked if there's a way for me to somehow highlight the popular shows that we have (for example, how Netflix identifies the top 10 every week on its platform). Is there any functional way to do this other than for me to create a tag an manually add shows?

Thanks in advance.

Trakt is a wonderful resource for this in general but outside of custom solutions I can't think of something that applies it specifically to your own library.

https://trakt.tv/shows/trending

https://trakt.tv/shows/popular

[jrubenol]

I'm a big fan of trakt also but indeed, doesn't identify what's in my library already. Maybe I'll feature request it . . . Like my current skin has a "highlight" section but it seems entirely random which isn't useful.

[Hitcher]

Popular how exactly?

[Karellen]

You could add a Tag to the TV Show. Then add that Tag as a main menu item on the home screen.
https://kodi.wiki/view/Video_library_tags
https://kodi.wiki/view/Custom_home_items

[Fuchs2468]

[font][font]Hallo zusammen, [/font][/font]

[font][font]meine Frau beschwert sich darüber, dass es zu schwierig ist, durch alle unsere Medien zu navigieren, als dass sie neue Sendungen finden könnte, die sie sehen möchte. [/font][font]Sie fragte, ob es für mich eine Möglichkeit gäbe, die beliebten Sendungen, die wir haben, irgendwie hervorzuheben (z. B. wie Netflix jede Woche die Top 10 auf seiner Plattform ermittelt). [/font][font]Gibt es eine andere Möglichkeit, dies zu tun, als dass ich ein Tag erstelle und Shows manuell hinzufüge?[/font][/font]

[font][font]Ja, das kannst du, ich habe es gerade mit TheMovieDb Helper und mit Embuary Info getestet. [/font][/font]
[font][font]In meinem Beispiel sind alle vorhandenen TV-Sendungen oder Filme mit einem Play-Button gekennzeichnet. [/font][/font]
[font][font]Vielleicht werde ich diese Funktion in meinen Skin Titan Mod integrieren. [/font][font]Ich denke, es ist eine nette Funktion. [/font][/font]

[font][font]Ich habe diesen Code zum Testen verwendet: [/font][/font]
[font][font]

xml:
 <control type="group"> [/font][/font]

[font][font]                <description>DBID Indicator</description> [/font][/font]

[font][font]                <visible>!String.IsEmpty(ListItem.DBID) + String.StartsWith(ListItem.FolderPath,[/font][/font]











[font][font]                        <texture>play.png</texture> [/font][/font]

[font][font]                        <colordiffuse>$INFO[Skin.String(WatchedIndicator.Watched.Color)]</colordiffuse> [/font][/font]

[font][font]                        <aspectratio scalediffuse="false" align="right">keep</aspectratio> [/font][/font]

[font][font]                    < /control> [/font][/font]

[font][font]            </control>

[/font][/font]

[Fuchs2468]

Hi All -

My wife is complaining that it's too hard to navigate through all of our media for her to find new shows that she might want to watch. She asked if there's a way for me to somehow highlight the popular shows that we have (for example, how Netflix identifies the top 10 every week on its platform). Is there any functional way to do this other than for me to create a tag an manually add shows?

Yes you can, I just tested it with TheMovieDb Helper and with Embuary Info.
In my example, all existing TV shows or movies are marked witha play button.
Maybe I will integrate this function into my skin Titan mod. I think it's a nice feature.

I used this code for testing:

xml:
            <control type="group">

                <description>DBID Indicator</description>

                <visible>!String.IsEmpty(ListItem.DBID) + String.StartsWith(ListItem.FolderPath,plugin)</visible>

                <control type="image">

                        <top>2</top>

                        <left>-80</left>

                        <width>50%</width>

                        <height>50%</height>

                        <texture>play.png</texture>

                        <colordiffuse>$INFO[Skin.String(WatchedIndicator.Watched.Color)]</colordiffuse>

                        <aspectratio scalediffuse="false" align="right">keep</aspectratio>

                    </control>

            </control>

[jrubenol]

I'm a little confused about what I'm seeing above. Is this pulling based on popularity somewhere? There's a lot of neat things that I think could be done in this realm including:

(1) Highlighting the peak "popularity" that can be found on TMDB;
(2) Sorting shows/movies by # of reviews and/or current popularity (or even historic popularity)
(3) If possible being able to filter by Netflix/Hulu/Amazon/Etc..... top 10 or whatever lists they have
(4) The most advanced/difficult would be an engine built into Kodi that actually has like "suggested for you" like streaming services do

Anyways, intrigued by the last post and looking for a bit of background explanation as to what I'm looking at.

[Hitcher]

As far as I can tell that's just indicating any videos from TMDB helpers lists that are in your own library.

[jrubenol]

As far as I can tell that's just indicating any videos from TMDB helpers lists that are in your own library.

Where is the list that it's comparing against? Could I compare it against a specific list such as:
https://www.themoviedb.org/tv?language=en-US

[Hitcher]

Install TheMovieDb Helper.

[scott967]

I don't use tbdb helper (I maintain extendedinfo script) but probably works about the same.  TMDB offers a list of popular or highest rated shows or movies.  That list could be filtered to show only library entries (don't know if tmdb helper does that?)

scott s.
.