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JSONRPC.NotifyAll - Help to send Notification via URL
#1
I want to show a popup notification in KODI.

Can anyone help me to build a json request via HTTP.
I want to send via HTTP command a simple Message.

I tried this, but I don't get any feedback back:
http://192.168.1.87:8080/jsonrpc?request={"jsonrpc": "2.0", "method": "JSONRPC.NotifyAll", "params": {"sender": "homee", "message": "Test"}, "id": 1}

If I try it I get no response back and no notifications inside Kodi.
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#2
I have a simple python program that can send a message to Kodi. I think if you do a search you should be able to find a way to do what you want via http, but I found it easier to just use python.
Code:
#!/bin/env/python
#updated on 3/15/2016 by Harry to pass parameters for title and message
#meassage parameter should be the filename of the file just processed by Comskip
#also utilizing xbmcjson due to easier interface.
#
#
import sys
import time
from xbmcjson import XBMC, PLAYER_VIDEO
# constants start
semi_colon = ';'
colon = ':'
comma = ','
slash = "\x5C"
back_slash = "\x2F"
question_mark = "\x3F"
char1 = "\x5E"
char2 = "\x7B"
char3 = "\x7D"
char4 = "\x7E"
# char5 = "\x7F"
char6 = "\x5D"
char7 = "\x5B"
underscore = "_"
dot = "."
dash = "-"
space = " "
quoate = "\x22"
debug_it = False
# Settings
# The IP address for the XBMC instance you want to talk to
ip = 'localhost'
#ip = '192.168.11.59'
# The port number XBMC's web interface is listening on
port = '8080'
#port = '80'
# The username on XBMC's web interface (just comment or delete this line if you don't use authentication
username = 'xbmc'
# Same as the username. No password for my system.
password = ''
#
json_name =  back_slash + "jsonrpc"
full_http = "http:" + back_slash + back_slash + ip + colon + port + json_name
xbmc = XBMC(full_http)
#
# Here you specify the method and parameters you want to pass to the XBMC JSON API
# For a LOT of info on the kinds of things you can do with the interface go here:
# http://wiki.xbmc.org/index.php?title=JSON-RPC_API/v6
# Here's an example of just sending an on-screen notification. This should help you understand the syntax
# method = 'GUI.ShowNotification'
# parameters = {"title":"Hello There!", "message":"This is a notification!", "displaytime":3000}
# This is what I am actually doing with this script, running the Artwork Downloader.
# Note: I am using the "silent" mode to avoid having a pop-up dialog box that would need to be closed.
# Also note: this stuff is very syntax-specific. Boolean and Int values must not be quoted. Strings must be doublequoted.
method = 'GUI.ShowNotification'
method2 = 'VideoLibrary.Clean'
method3 = 'VideoLibrary.Scan'
notify_method = method
libclean_method = method2
libscan_method = method3
# parameters = {'title': "Comskip completed for:",'message': "A recorded program"}
# above is original format. Trying in final version to pass a filename as a parameter
# below line is a test line with variable input
recorded_program = ""
# No Program Name Provided"
# constants start
slash = "\\"
underscore = "_"
dot = "."
iplist_file = 'IPList.txt'
# constants end
arguments = len(sys.argv)
#print ("Parameters received = ",arguments)
#argument [0] is the name of the Python program being executed.
#argument [1] is the parameter being passed to the Python program as the message
#argument [2] is the parameter being passed to the Python program as the title
title_text = "Comskip Completed."
if arguments >= 2 :
         title_text = sys.argv[1]
         if arguments >= 3:
                 recorded_program = sys.argv[2]
                 if arguments >= 4:
                          ip = sys.argv[3]
                          if arguments >= 3:
                                   port = sys.argv[4]
         json_name =  back_slash + "jsonrpc"
         full_http = "http:" + back_slash + back_slash + ip + colon + port + json_name
         xbmc = XBMC(full_http)
if arguments == 1 :
        recorded_program = sys.argv[0]
str1 = recorded_program
str2 = str1.rpartition(slash)[2]
str3 = str2.partition(dot)[0]
if debug_it:
         print "str1=",str1, "str2=",str2, "str3=",str3
str4 = str3.partition(underscore)
if debug_it:
         print "str4= ",str4
recorded_program = str4[0]
if debug_it:
         print "str4 =", str4, "recorded program = ",recorded_program
parameters = {'title': title_text,'message': recorded_program}

# This is a single, reusable method that makes a call to XBMC and gives you back the response

def sendJson(url_in,method,parameters):
        #
        results = 0
        temp_str = url_in
        xbmc = XBMC(temp_str)
        if method == notify_method:
                #xbmc.method(parameters)
                results = xbmc.GUI.ShowNotification(parameters)
                #title="Library Clean", message = "Initiated")
        else:
                if method == libscan_method:
                        if "win" in sys.platform:
                                if ip in url_in:
                                        results = xbmc.VideoLibrary.Scan(parameters)
                                else:
                                        results = xbmc.VideoLibrary.Scan()
                        else:
                                results = xbmc.VideoLibrary.Scan()
                else:
                        if method == libclean_method:
                                results = xbmc.VideoLibrary.Clean()
        if debug_it:
                print results
        return results['result']
#

# Here's an example of using the above method and variable values to make XBMC show a Notify
results =sendJson(full_http,method,parameters)
time.sleep(2)
# I just print the results out
print "results= ", results, " from ", full_http
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#3
Thanks, but does no one use the Notifications with HTTP?
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#4
Thumbs Up 
Works now, so it is solved!
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#5
Hey Chris,

would you mind sharing your solution?

Thanks
Karl
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#6
Yes of course.

Here is the URL base:
http://192.168.1.87:8080/jsonrpc?request=

And the parameters are:
{"jsonrpc": "2.0", "method": "GUI.ShowNotification", "params": {"title": "HERE ADD THE TITLE", "message": "ADD THE MESSAGE HERE" }, "id": 1}
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#7
(2017-09-17, 13:25)chrisonline1205 Wrote: Yes of course.

Here is the URL base:
http://192.168.1.87:8080/jsonrpc?request=

And the parameters are:
{"jsonrpc": "2.0", "method": "GUI.ShowNotification", "params": {"title": "HERE ADD THE TITLE", "message": "ADD THE MESSAGE HERE" }, "id": 1}

This has worked for me to for a long time, but no longer works in Kodi Leia
i get an 
{"error":{"code":-32099,"message":"Bad client permission."},"id":1,"jsonrpc":"2.0"}
cant figure it out on what to change or use next 
any sugestions ?
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#8
(2020-11-25, 11:30)Richard6360 Wrote:
(2017-09-17, 13:25)chrisonline1205 Wrote: Yes of course.

Here is the URL base:
http://192.168.1.87:8080/jsonrpc?request=

And the parameters are:
{"jsonrpc": "2.0", "method": "GUI.ShowNotification", "params": {"title": "HERE ADD THE TITLE", "message": "ADD THE MESSAGE HERE" }, "id": 1}

This has worked for me to for a long time, but no longer works in Kodi Leia
i get an 
{"error":{"code":-32099,"message":"Bad client permission."},"id":1,"jsonrpc":"2.0"}
cant figure it out on what to change or use next 
any sugestions ?

This can be the problem.
Since LEIA the GET does not support actions.

We need to use POST.
I have not tried it yet so can you check if you can set as "protocol" "POST?

Image
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JSONRPC.NotifyAll - Help to send Notification via URL0